(x^3-2)(x^2+4x-1)+x=0

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Solution for (x^3-2)(x^2+4x-1)+x=0 equation: 


Simplifying
(x3 + -2)(x2 + 4x + -1) + x = 0

Reorder the terms:
(-2 + x3)(x2 + 4x + -1) + x = 0

Reorder the terms:
(-2 + x3)(-1 + 4x + x2) + x = 0

Multiply (-2 + x3) * (-1 + 4x + x2)
(-2(-1 + 4x + x2) + x3(-1 + 4x + x2)) + x = 0
((-1 * -2 + 4x * -2 + x2 * -2) + x3(-1 + 4x + x2)) + x = 0
((2 + -8x + -2x2) + x3(-1 + 4x + x2)) + x = 0
(2 + -8x + -2x2 + (-1 * x3 + 4x * x3 + x2 * x3)) + x = 0
(2 + -8x + -2x2 + (-1x3 + 4x4 + x5)) + x = 0
(2 + -8x + -2x2 + -1x3 + 4x4 + x5) + x = 0

Reorder the terms:
2 + -8x + x + -2x2 + -1x3 + 4x4 + x5 = 0

Combine like terms: -8x + x = -7x
2 + -7x + -2x2 + -1x3 + 4x4 + x5 = 0

Solving
2 + -7x + -2x2 + -1x3 + 4x4 + x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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